BlackFriday 2024! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions

Splunk Exam SPLK-1002 Topic 6 Question 95 Discussion

Actual exam question for Splunk's SPLK-1002 exam
Question #: 95
Topic #: 6
[All SPLK-1002 Questions]

Which of these stats commands will show the total bytes for each unique combination of page and server?

Show Suggested Answer Hide Answer
Suggested Answer: B

The correct command to show the total bytes for each unique combination of page and server isindex=web | stats sum (bytes) BY page server. In Splunk, thestatscommand is used to calculate aggregate statistics over the dataset, such as count, sum, avg, etc. When using theBYclause, it groups the results by the specified fields. The correct syntax does not include commas or the word 'AND' between the field names. Instead, it simply lists the field names separated by spaces within theBYclause.

Reference: The usage of thestatscommand with theBYclause is confirmed by examples in the Splunk Community, where it's explained thatstatswith aby foo barwill output one row for every unique combination of thebyfields1.


Contribute your Thoughts:

Cecilia
2 months ago
I believe D) index=web | stats sum(bytes) BY values (page) values (server) is incorrect because it uses 'values' instead of 'BY'.
upvoted 0 times
...
Dortha
2 months ago
I'm not sure, but I think C) index=web | stats sum(bytes) BY page AND server might also work.
upvoted 0 times
...
Rory
2 months ago
Wait, is this a Splunk question? If so, I'm pretty sure A is the way to go. Gotta love those Splunk commands!
upvoted 0 times
Kanisha
18 days ago
B) index=web | stats sum (bytes) BY page server
upvoted 0 times
...
Johnna
1 months ago
Definitely! Splunk commands can be tricky, but A seems like the right choice.
upvoted 0 times
...
Quiana
1 months ago
A) index=web | stats sum (bytes) BY page BY server
upvoted 0 times
...
...
Devorah
2 months ago
Haha, I bet the person who wrote this question is a real stat-geek! But I'm still going with A.
upvoted 0 times
Edison
1 months ago
Let's go with A then.
upvoted 0 times
...
Mignon
1 months ago
I'm not sure, but A sounds logical.
upvoted 0 times
...
Darci
2 months ago
I agree, A seems like the right choice.
upvoted 0 times
...
Lai
2 months ago
I think A is the correct answer.
upvoted 0 times
...
...
Veta
2 months ago
D seems a bit weird to me. The 'values' function is not something I'm familiar with in this context.
upvoted 0 times
Tran
1 months ago
D seems a bit weird to me. The 'values' function is not something I'm familiar with in this context.
upvoted 0 times
...
Phil
1 months ago
B) index=web | stats sum (bytes) BY page server
upvoted 0 times
...
Marti
1 months ago
A) index=web | stats sum (bytes) BY page BY server
upvoted 0 times
...
...
Margot
2 months ago
I'm going with C. The 'AND' keyword makes it clear that we want to group by both page and server.
upvoted 0 times
Elin
2 months ago
C) index=web | stats sum(bytes) BY page AND server
upvoted 0 times
...
Marjory
2 months ago
A) index=web | stats sum (bytes) BY page BY server
upvoted 0 times
...
...
Willard
3 months ago
I agree with Sonia, because we need to show the total bytes for each unique combination of page and server.
upvoted 0 times
...
Rosendo
3 months ago
Option B looks good to me. It has the same grouping as A, but in a more concise way.
upvoted 0 times
Malcolm
2 months ago
I believe option A is the right choice because it specifically groups by page and server.
upvoted 0 times
...
Lorrie
2 months ago
I agree with you, option B seems more concise and still groups by both page and server.
upvoted 0 times
...
Louvenia
2 months ago
I think option A is the correct one. It groups by both page and server.
upvoted 0 times
...
...
Sonia
3 months ago
I think the answer is A) index=web | stats sum (bytes) BY page BY server.
upvoted 0 times
...
Malcolm
3 months ago
I think option A is the correct one. It groups the data by both page and server, which is what the question is asking for.
upvoted 0 times
Juan
2 months ago
Option D doesn't look right, it's using values instead of BY.
upvoted 0 times
...
King
2 months ago
I'm not sure about option C, it seems a bit off.
upvoted 0 times
...
Janet
2 months ago
I think option B might work too, it groups by both page and server.
upvoted 0 times
...
Portia
2 months ago
I agree, option A is the correct one.
upvoted 0 times
...
...

Save Cancel