New Year Sale 2026! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions
Mail Us support@pass4success.com
Location US
Mob_nav_barsMENU

Snowflake DSA-C02 Exam - Topic 3 Question 32 Discussion

Actual exam question for Snowflake's DSA-C02 exam
Question #: 32
Topic #: 3
[All DSA-C02 Questions]

Consider a data frame df with columns ['A', 'B', 'C', 'D'] and rows ['r1', 'r2', 'r3']. What does the ex-pression df[lambda x : x.index.str.endswith('3')] do?

Show Suggested Answer Hide Answer
Suggested Answer: D

It will Filters the row labelled r3.


by Annette at Sep 18, 2024, 06:56 AM

Limited Time Offer

25%

Off

Get Premium DSA-C02 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

0/2000 characters
Submit Cancel
Simona
3 months ago
Sounds too simple, I doubt that's all it does.
upvoted 0 times
...
Lottie
3 months ago
Just returns r3, nothing else.
upvoted 0 times
...
Lashawn
4 months ago
Wait, are we sure it doesn't throw an error?
upvoted 0 times
...
Ilda
4 months ago
Totally agree, it's D for sure!
upvoted 0 times
...
Marvel
4 months ago
It filters the row labelled r3.
upvoted 0 times
...
Bette
4 months ago
If I remember correctly, df[lambda x: x.index.str.endswith('3')] should filter and return the row with index r3, so I think option D is correct.
upvoted 0 times
...
Lashawnda
4 months ago
I’m a bit confused; I thought using a lambda function like that might cause an error, but I can't recall if that's the case here.
upvoted 0 times
...
Jamika
5 months ago
I remember practicing a similar question where we filtered rows using conditions, so I feel like it should return the row labelled r3.
upvoted 0 times
...
Samira
5 months ago
I think the expression is supposed to filter rows based on their index, but I'm not entirely sure if it will return just r3 or something else.
upvoted 0 times
...
Tarra
5 months ago
This is a tricky one. I'm not entirely sure what the lambda function is doing, but I think it might be trying to filter the DataFrame by the row labels. I'll have to experiment with this type of indexing to be sure.
upvoted 0 times
...
Glenna
5 months ago
Okay, I think I've got it. The lambda function is checking if each row index string ends with '3', so it should return just the row with index 'r3'. That makes sense to me.
upvoted 0 times
...
Valentine
5 months ago
I'm a bit confused by this one. The lambda function is using the str.endswith() method, but I'm not sure how that applies to the DataFrame indexing. I'll need to think this through carefully.
upvoted 0 times
...
Jolene
5 months ago
Hmm, this looks like it's testing our understanding of how to use lambda functions with DataFrame indexing. I think the key is figuring out what the lambda function is doing to the index.
upvoted 0 times
...
Serina
1 year ago
This is a tough one, but I think I've got it. The lambda function is checking the row index, so the correct answer must be D. Though I can't help but wonder if the data frame is secretly a sentient being, just waiting to surprise us all.
upvoted 0 times
Eden
1 year ago
Haha, who knows, maybe the data frame is secretly sentient!
upvoted 0 times
...
Joesph
1 year ago
So the correct answer must be D.
upvoted 0 times
...
Cristy
1 year ago
I agree, the lambda function is checking the row index.
upvoted 0 times
...
Camellia
1 year ago
Haha, that would be quite the surprise if the data frame turned out to be sentient!
upvoted 0 times
...
Maurine
1 year ago
I think the correct answer is D, as it filters the row labelled r3.
upvoted 0 times
...
Izetta
1 year ago
I agree with you, the lambda function is indeed checking the row index.
upvoted 0 times
...
Ozell
1 year ago
I think you're right, it filters the row labelled r3.
upvoted 0 times
...
...
Estrella
1 year ago
Easy peasy! The lambda function is looking for rows where the index ends with '3', so the answer has to be D. Though I do wonder if the data frame has a sense of humor and will throw an error just to mess with us.
upvoted 0 times
...
Avery
1 year ago
Haha, the lambda function is like a secret code that only data scientists can crack! I'm going to go with D, because filtering rows seems like the most logical choice here.
upvoted 0 times
...
Gertude
1 year ago
Hmm, I'm not so sure about this one. It could be C, since the lambda function might be selecting the third column. But I'm leaning towards D, just to be safe.
upvoted 0 times
Deangelo
1 year ago
I'm not sure, but I think it could be A, returning the row name r3.
upvoted 0 times
...
Lea
1 year ago
Okay, let's go with D then.
upvoted 0 times
...
Luisa
1 year ago
I agree with User2, D seems more likely.
upvoted 0 times
...
Jesusita
1 year ago
I believe it's C, returning the third column.
upvoted 0 times
...
Bettina
1 year ago
I think it might be D too, filtering the row labelled r3.
upvoted 0 times
...
Leonie
1 year ago
I think it might be C, selecting the third column.
upvoted 0 times
...
Matthew
1 year ago
I'm not sure, I think it could be D, filtering the row labelled r3.
upvoted 0 times
...
...
Pauline
1 year ago
This is a tricky one! I think the correct answer is D, since the lambda function checks if the row index ends with '3', which would filter out just the row labeled 'r3'.
upvoted 0 times
Vanda
1 year ago
I believe it would result in an error, so I would go with B.
upvoted 0 times
...
Margart
1 year ago
I'm not sure, but I think it might be A.
upvoted 0 times
...
Paris
1 year ago
I think you're right, D seems like the correct answer.
upvoted 0 times
...
...
Virgie
1 year ago
That makes sense, so the answer is D) Filters the row labelled r3.
upvoted 0 times
...
Carman
1 year ago
I think it filters the row labelled r3.
upvoted 0 times
...
Virgie
1 year ago
What does df[lambda x : x.index.str.endswith('3')] do?
upvoted 0 times
...

Save Cancel