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Snowflake Exam DSA-C02 Topic 2 Question 38 Discussion

Actual exam question for Snowflake's DSA-C02 exam

Question #: 38
Topic #: 2

[All DSA-C02 Questions]

All Snowpark ML modeling and preprocessing classes are in the ________ namespace?

Asnowpark.ml.modeling

Bsnowflake.sklearn.modeling

Csnowflake.scikit.modeling

Dsnowflake.ml.modeling

Show Suggested Answer

Suggested Answer: D

All Snowpark ML modeling and preprocessing classes are in the snowflake.ml.modeling namespace. The Snowpark ML modules have the same name as the corresponding module from the sklearn namespace. For example, the Snowpark ML module corresponding to sklearn.calibration is snow-flake.ml.modeling.calibration.

The xgboost and lightgbm modules correspond to snowflake.ml.modeling.xgboost and snow-flake.ml.modeling.lightgbm, respectively.

Not all of the classes from scikit-learn are supported in Snowpark ML.

by Sophia at Feb 08, 2025, 06:16 PM

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Carmen

10 days ago

I bet the developers at Snowflake had a heated debate over whether to use 'modeling' or 'ML' in the namespace. The puns must have been endless.

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My

14 days ago

B and C are just silly options. Who even uses 'sklearn' or 'scikit' with Snowflake? A or D are the only real contenders.

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Beth

21 days ago

D sounds like the most logical choice to me. Snowflake's ML namespace would make the most sense.

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Rima

5 days ago

I think D is the correct answer too. It just makes sense.

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Hermila

14 days ago

Yeah, snowflake.ml.modeling sounds like the right namespace.

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Jose

18 days ago

I think D is the correct answer too.

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Gilberto

29 days ago

I'm not sure, but I think it's D) snowflake.ml.modeling

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Belen

1 months ago

I agree with Veronica, A) snowpark.ml.modeling makes sense

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Karrie

1 months ago

Hmm, I think it's option A. After all, the question specifically mentions 'Snowpark' in the wording.

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Cordelia

2 days ago

I'm not sure, but I'll go with option A as well.

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Joesph

11 days ago

I think so too, it makes sense given the context of the question.

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Dulce

23 days ago

I agree, option A seems like the most logical choice.

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Veronica

1 months ago

I think it's A) snowpark.ml.modeling

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a