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Snowflake Exam DSA-C02 Topic 2 Question 28 Discussion

Actual exam question for Snowflake's DSA-C02 exam
Question #: 28
Topic #: 2
[All DSA-C02 Questions]

All Snowpark ML modeling and preprocessing classes are in the ________ namespace?

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Suggested Answer: D

All Snowpark ML modeling and preprocessing classes are in the snowflake.ml.modeling namespace. The Snowpark ML modules have the same name as the corresponding module from the sklearn namespace. For example, the Snowpark ML module corresponding to sklearn.calibration is snow-flake.ml.modeling.calibration.

The xgboost and lightgbm modules correspond to snowflake.ml.modeling.xgboost and snow-flake.ml.modeling.lightgbm, respectively.

Not all of the classes from scikit-learn are supported in Snowpark ML.


Contribute your Thoughts:

Tran
16 days ago
I'm not sure, but I think it's D) snowflake.ml.modeling
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Malcolm
17 days ago
I agree with Nikita, A) snowpark.ml.modeling makes sense
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Nikita
19 days ago
I think it's A) snowpark.ml.modeling
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Vallie
19 days ago
I'm still waiting for Snowflake to come up with a namespace called 'snowlake.ml.modeling' just to keep us on our toes.
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Gerald
27 days ago
Hmm, this is a tough one. I'm going to go with A, but I really hope I don't get snow-blindness from all this Snowpark talk.
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Michal
28 days ago
B and C sound like they're trying to trick us. Snowflake doesn't use scikit-learn or sklearn, so those can't be right.
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Felix
29 days ago
I'm leaning towards D. Snowflake has its own ML capabilities, so the namespace would be snowflake.ml.modeling.
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Jacquelyne
7 days ago
I'm not sure, but I believe it's D) snowflake.ml.modeling.
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Kimberely
16 days ago
I think it's A) snowpark.ml.modeling.
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Essie
1 months ago
I'm pretty sure it's A. Snowpark is Snowflake's own ML platform, so the namespace would be snowpark.ml.modeling.
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Teddy
16 days ago
Yes, you're correct. Snowpark ML modeling classes are in the snowpark.ml.modeling namespace.
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Micaela
30 days ago
I think you're right, it should be A) snowpark.ml.modeling.
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