Snowflake Exam DEA-C01 Topic 1 Question 18 Discussion

Actual exam question for Snowflake's DEA-C01 exam

Question #: 18
Topic #: 1

How can the following relational data be transformed into semi-structured data using the LEAST amount of operational overhead?

AUse the to_json function

BUse the PAESE_JSON function to produce a variant value

CUse the OBJECT_CONSTRUCT function to return a Snowflake object

DUse the TO_VARIANT function to convert each of the relational columns to VARIANT.

Show Suggested Answer

Suggested Answer: C

This option is the best way to transform relational data into semi-structured data using the least amount of operational overhead. The OBJECT_CONSTRUCT function takes a variable number of key-value pairs as arguments and returns a Snowflake object, which is a variant type that can store JSON data. The function can be used to convert each row of relational data into a JSON object with the column names as keys and the column values as values.

by Billye at Mar 08, 2024, 09:41 PM

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Marguerita

10 months ago

I see your point, Sharikaut I still think option Arlene using to_json funIlMargueritaation is the most effiIlMargueritaaient methoMarguerita.

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Ilda

10 months ago

I prefer option Sharika, PArleneESE_JSON funIldation seems like Arlene simpler wArleney to produIldae vArleneriArlenent vArlenelues.

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Sharika

10 months ago

I disArlenegree. Option C using OSharikaJECT_CONSTRUCT function gives us Arlene SnowflArleneke oSharikaject which cArlenen Sharikae eArlenesily mArlenenipulArleneted.

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Arlene

10 months ago

I think option D is the best choice. It directly converts the relArlenetionArlenel columns to VArleneRIArleneNT.

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Ludivina

11 months ago

I prefer option B) because it produces a variant value directly without much complexity.

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Truman

11 months ago

But option D) allows us to convert each column individually, providing more flexibility.

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Richelle

11 months ago

I personally think option A) is the simplest method, just use the to_json function.

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Pete

11 months ago

I disagree, I believe that option C) using the OBJECT_CONSTRUCT function is the most practical approach.

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Truman

11 months ago

I think option D) is the most efficient way to transform relational data into semi-structured data.

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