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SAP Exam C_ABAPD_2309 Topic 4 Question 31 Discussion

Actual exam question for SAP's C_ABAPD_2309 exam
Question #: 31
Topic #: 4
[All C_ABAPD_2309 Questions]

Given the following Core Data Service View Entity Data Definition:

1 @AccessControl.authorizationCheck: #NOT_REQUIRED

2 DEFINE VIEW ENTITY demo_flight_info_join

3 AS SELECT

4 FROM scarr AS a

5 LEFT OUTER JOIN scounter AS c

6 LEFT OUTER JOIN sairport AS p

7 ON p.id = c.airport

8 ON a.carrid = c.carrid

9 {

10 a.carrid AS carrier_id,

11 p.id AS airport_id,

12 c.countnum AS counter_number

13 }

In what order will the join statements be executed?

Show Suggested Answer Hide Answer
Suggested Answer: A

The order in which the join statements will be executed is:

scarr will be joined with scounter first and the result will be joined with sairport.

This is because the join statements are nested from left to right, meaning that the leftmost data source is joined with the next data source, and the result is joined with the next data source, and so on. The join condition for each pair of data sources is specified by the ON clause that follows the data source name. The join type for each pair of data sources is specified by the join operator that precedes the data source name. In this case, the join operator is LEFT OUTER JOIN, which means that all the rows from the left data source are included in the result, and only the matching rows from the right data source are included. If there is no matching row from the right data source, the corresponding fields are filled with initial values1.

Therefore, the join statements will be executed as follows:

First, scarr AS a will be joined with scounter AS c using the join condition a.carrid = c.carrid. This means that all the rows from scarr will be included in the result, and only the rows from scounter that have the same value for the carrid field will be included. If there is no matching row from scounter, the countnum field will be filled with an initial value.

Second, the result of the first join will be joined with sairport AS p using the join condition p.id = c.airport. This means that all the rows from the first join will be included in the result, and only the rows from sairport that have the same value for the id field as the airport field from the first join will be included. If there is no matching row from sairport, the id field will be filled with an initial value.


Contribute your Thoughts:

Peggy
26 days ago
This is a tricky one. I'm going to go with C, but I'm not entirely confident. Guess I need to brush up on my SQL join knowledge.
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Luis
8 days ago
I believe it's B) sairport will be joined to scounter first and the result will be joined with scarr.
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Serita
15 days ago
I think the join order is A) scarr will be joined with scounter first and the result will be joined with sairport.
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King
1 months ago
I agree with Ilene. The join order should be scarr, sairport, scounter.
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Ilene
1 months ago
I think the answer is C.
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Nan
1 months ago
Haha, I bet the exam writer is trying to trip us up with those LEFT OUTER joins. I'm going with B, just to be different!
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Lashon
1 months ago
Hmm, I'm not so sure. The statement says the joins are LEFT OUTER, which means the order could impact the results. I'm leaning towards D, but I'll have to double-check the SQL join order of operations.
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Audra
16 days ago
That makes sense, the order of LEFT OUTER joins can impact the final result.
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Pearly
20 days ago
I believe scounter will be joined to sairport first and then with scarr.
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Roslyn
24 days ago
I agree, LEFT OUTER joins can affect the results based on the order.
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Merrilee
1 months ago
I think the order of the joins is important in this case.
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Felix
2 months ago
I think the answer is C. The joins are specified in the order scarr to scounter, then scounter to sairport, so the execution order will follow that.
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Benedict
10 days ago
No, I think the correct answer is B. sairport will be joined to scounter first.
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Nickie
18 days ago
I'm not sure about that. I think the answer might be A, with scarr joining scounter first.
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Devorah
23 days ago
I think you're right. The joins will be executed in the order scarr to sairport first, then scounter.
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Hoa
29 days ago
I agree with you, the answer is C. The joins are executed in the order specified in the query.
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Krissy
1 months ago
That makes sense. The order of joins in the query determines the execution order.
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Ahmed
1 months ago
Yes, the joins will be executed in the order scarr to sairport first, then sairport to scounter.
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Mira
2 months ago
I agree with you, the answer is C. The joins are executed in the order specified in the query.
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