Python Institute Exam PCPP-32-101 Topic 8 Question 34 Discussion

Actual exam question for Python Institute's PCPP-32-101 exam

Question #: 34
Topic #: 8

[All PCPP-32-101 Questions]

A socket object is usually created by which one of the following invocations?

Asocket. socket (socket_domain, socket_type)

Bsocket = socket. socket (socket_number)

Csocket = socket. socket (socket_domain, socket_type, server_address)

Dsocket = socket.socket(server address)

Show Suggested Answer

Suggested Answer: D

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by Zita at Sep 13, 2024, 02:04 AM

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Penney

2 months ago

Option A, because creating sockets is as easy as A-B-C... D is for dummies.

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Zona

10 days ago

Yeah, D is definitely not the right choice.

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Jutta

15 days ago

I agree, creating sockets is as easy as A-B-C.

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Cecilia

24 days ago

I think A is the correct option.

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Sommer

2 months ago

I'm going with B. It's simple and straight to the point, just like my coding style.

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Sanda

11 days ago

User 3: B sounds good to me, simple is always better.

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Adell

12 days ago

User 2: I'm going with C, it seems more comprehensive.

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Novella

27 days ago

User 1: I think A is the correct answer.

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Percy

2 months ago

D is clearly the wrong answer. You can't create a socket by just passing the server address. That doesn't make any sense.

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Jamal

2 months ago

I think C is the correct answer. The socket.socket() function takes three arguments: the socket domain, socket type, and the server address.

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Aleisha

16 days ago

Actually, B) socket = socket. socket (socket_number) is the correct answer.

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Casie

1 months ago

I'm pretty sure it's D) socket = socket.socket(server address).

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Nan

1 months ago

No, I think it's A) socket. socket (socket_domain, socket_type).

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Annamae

2 months ago

I agree, C is the correct answer.

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Carline

3 months ago

Option A looks right to me. The socket module has a function called socket() that takes the socket domain and type as arguments.

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Caprice

1 months ago

Great, thanks for clarifying that!

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Xuan

1 months ago

So, the correct invocation is socket.socket(socket_domain, socket_type).

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Jess

2 months ago

User 2: Yes, that's correct. The socket module has a function called socket() that takes the socket domain and type as arguments.

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Jodi

2 months ago

Yes, I agree. The socket module's socket() function takes the domain and type as arguments.

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Margot

2 months ago

I think option A is correct.

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Maxima

2 months ago

User 1: I think the answer is A) socket. socket (socket_domain, socket_type)

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Katie

3 months ago

I'm not sure, but I think D) socket = socket.socket(server address) doesn't seem right

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Miriam

3 months ago

I believe it's C) socket = socket.socket(socket_domain, socket_type, server_address)

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Ludivina

3 months ago

I think the answer is A) socket.socket(socket_domain, socket_type)

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