PRMIA Exam 8002 Topic 3 Question 85 Discussion

Actual exam question for PRMIA's Mathematical Foundations of Risk Measurement :II exam

Question #: 85
Topic #: 3

[All Mathematical Foundations of Risk Measurement :II Questions]

What can be said about observations of random variables that are i.i.d. a normally distributed?

AThe estimated mean divided by the estimated variance has a t-distribution

BThe estimated mean divided by the estimated variance has a Chi2-distribution

CThe estimated mean divided by the estimated standard deviation has a t-distribution

DThe estimated mean divided by the estimated standard deviation has a Chi2-distribution

Show Suggested Answer

Suggested Answer: C

by Wynell at Jul 12, 2024, 04:11 PM

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Iola

2 months ago

Wait, isn't the estimated mean divided by the estimated standard deviation supposed to have a normal distribution? I'm so confused right now.

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Bernardine

1 months ago

No, it actually has a Chi2-distribution.

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Carissa

1 months ago

User 1: The estimated mean divided by the estimated standard deviation has a t-distribution.

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Teddy

2 months ago

I agree with Bette, I also think the answer is A.

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Thomasena

2 months ago

Haha, I bet the exam writer is having a field day coming up with these trick questions. Jokes on us, the students!

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Ling

2 months ago

I'm not sure, but I think it might be D.

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Reta

2 months ago

Really? I was sure it was the estimated mean divided by the estimated variance that has a t-distribution. This exam is testing my knowledge of statistical distributions!

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Mica

1 months ago

Laila: Oh, I see. Thanks for clarifying!

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Thad

1 months ago

I believe the estimated mean divided by the estimated variance has a Chi2-distribution.

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Laila

1 months ago

No, actually it's the estimated mean divided by the estimated standard deviation that has a t-distribution.

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Ashlyn

1 months ago

User 1: I think it's the estimated mean divided by the estimated variance that has a t-distribution.

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Alverta

2 months ago

I disagree, I believe the answer is C.

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Bronwyn

2 months ago

Hmm, this question is a bit tricky. I think the answer is C, since the estimated mean divided by the estimated standard deviation should follow a t-distribution.

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