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PRMIA Exam 8002 Topic 2 Question 93 Discussion

Actual exam question for PRMIA's 8002 exam
Question #: 93
Topic #: 2
[All 8002 Questions]

Let N(.) denote the cumulative distribution function and suppose that X and Y are standard normally distributed and uncorrelated. Using the fact that N(1.96)=0.975, the probability that X 0 and Y 1.96 is approximately

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Suggested Answer: B

by Hobert at Sep 15, 2024, 09:53 AM

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Merilyn
1 months ago
Ah, the age-old question of normal distribution probabilities. You know, back in my day, we had to do these calculations by hand, with a slide rule and a protractor. These kids today, with their fancy computers and calculators, they don't know how good they've got it. Anyway, the answer is C) 0.49%, no doubt about it.
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Jani
1 months ago
Wait, wait, wait. Is this a trick question? I mean, who even uses normal distribution tables anymore? Can't we just run this through a Python script and be done with it? Anyway, my money's on B) 0.488%. *crosses fingers*
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Princess
1 months ago
I'm not sure, but I think the answer might be C) 0.49%
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Charlene
1 months ago
Okay, let's think this through step-by-step. X and Y are standard normal, and we're looking for the probability that X is greater than or equal to 0 and Y is greater than or equal to 1.96. Using the table, that's gotta be C) 0.49%. This is a piece of cake!
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Cristy
13 days ago
You're right, it's C) 0.49%
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Chaya
15 days ago
No, I believe it's C) 0.49%
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Buddy
27 days ago
I think the answer is B) 0.488%
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Rosalyn
1 months ago
I agree with Boris, because N(1.96) = 0.975, so the probability should be close to 0.488%
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Valentin
1 months ago
Ah, the old standard normal distribution problem. I've got this one in the bag. The answer is clearly D) 0.495%, because I'm always right about these things. Well, most of the time.
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Alise
1 months ago
Hmm, this seems like a job for my secret weapon - the trusty normal distribution table. Let's see, 1.96 corresponds to 0.975, so the answer must be C) 0.49%.
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Brice
2 days ago
Great job using the normal distribution table to solve this problem!
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Denny
3 days ago
I agree, C) 0.49% seems like the correct probability.
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Judy
5 days ago
That makes sense, using the normal distribution table is always helpful.
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Evangelina
19 days ago
I think you're right, the answer should be C) 0.49%.
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Boris
2 months ago
I think the answer is B) 0.488%
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