Okay, let's see... If the random variables are i.i.d. and normally distributed, then the estimated mean divided by the estimated standard deviation should have a t-distribution. I think 'C' is the correct answer.
I'm pretty sure the estimated mean divided by the estimated variance has a Chi2-distribution. The standard deviation is just the square root of the variance, right?
Linwood
6 months agoLauran
6 months agoFrancoise
6 months agoChara
6 months agoLarae
5 months agoLauran
5 months agoDottie
5 months agoIsadora
5 months agoIlene
6 months agoOllie
6 months agoAnnmarie
6 months agoPhillip
6 months agoMertie
6 months agoLenna
6 months agoLeonardo
6 months agoArt
6 months ago