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PRMIA Exam 8002 Topic 1 Question 83 Discussion

Actual exam question for PRMIA's 8002 exam
Question #: 83
Topic #: 1
[All 8002 Questions]

Find the roots, if they exist in the real numbers, of the quadratic equation

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Suggested Answer: C

by Kanisha at Jul 03, 2024, 02:58 AM

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Linwood
9 months ago
I think Lauran is correct, as the t-distribution is used when estimating the mean divided by the standard deviation.
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Lauran
9 months ago
I believe the estimated mean divided by the estimated standard deviation has a t-distribution, not the variance.
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Francoise
9 months ago
I agree with Art, because when observations are i.i.d. and normally distributed, the ratio follows a t-distribution.
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Chara
9 months ago
Okay, let's see... If the random variables are i.i.d. and normally distributed, then the estimated mean divided by the estimated standard deviation should have a t-distribution. I think 'C' is the correct answer.
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Larae
8 months ago
Oh, I see. Thanks for clarifying!
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Lauran
8 months ago
No, it's actually the estimated mean divided by the estimated standard deviation that has a t-distribution.
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Dottie
9 months ago
But isn't it the estimated mean divided by the estimated variance that has a t-distribution?
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Isadora
9 months ago
I agree, 'C' is the correct answer.
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Ilene
9 months ago
Haha, I'm just going to guess 'C' and hope for the best. Statistics questions can be such a mind-bender!
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Ollie
10 months ago
I'm pretty sure the estimated mean divided by the estimated variance has a Chi2-distribution. The standard deviation is just the square root of the variance, right?
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Annmarie
9 months ago
That's right. The standard deviation is the square root of the variance.
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Phillip
9 months ago
Yes, you're correct. The estimated mean divided by the estimated variance has a Chi2-distribution.
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Mertie
10 months ago
The estimated mean divided by the estimated standard deviation has a t-distribution? That's a tough one. Let me think about it for a bit.
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Lenna
9 months ago
No, I believe it actually has a Chi2-distribution.
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Leonardo
9 months ago
I think the estimated mean divided by the estimated standard deviation has a t-distribution.
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Art
10 months ago
I think the estimated mean divided by the estimated variance has a t-distribution.
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