BlackFriday 2024! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions

OutSystems Exam Associate-Reactive-Developer Topic 1 Question 15 Discussion

Actual exam question for OutSystems's Associate-Reactive-Developer exam
Question #: 15
Topic #: 1
[All Associate-Reactive-Developer Questions]

For Aggregate as shown below, Ask filter to find the person whose name contains the string "John"

Show Suggested Answer Hide Answer
Suggested Answer: C

Contribute your Thoughts:

Shayne
7 months ago
You know, I was thinking the same thing about option D. It's just too literal. I'm with you guys on option C - that's the most robust and flexible way to handle this kind of partial string match.
upvoted 0 times
Jenelle
7 months ago
Let's go with option C, it's the most versatile for finding 'John' in the name.
upvoted 0 times
...
Lynelle
7 months ago
I see your point, option D is too specific for this scenario.
upvoted 0 times
...
Jennifer
7 months ago
Definitely option C, it covers all possibilities for the string 'John'.
upvoted 0 times
...
Ciara
7 months ago
I think option A is too strict, we need something more flexible like option C.
upvoted 0 times
...
Rutha
7 months ago
I agree with you, option C is the best choice here.
upvoted 0 times
...
...
Tequila
7 months ago
Haha, option D. 'John'. That's just silly. As if someone's name would be literally just 'John' with no other characters. These exam questions really try to trip you up sometimes, don't they?
upvoted 0 times
...
Charlene
7 months ago
Yeah, I agree with you on option C. The `like` operator is perfect for this kind of partial string match. The other options are too specific - option A would only match exact names of "John", and option D would be case-sensitive, which might not be what the exam is looking for.
upvoted 0 times
...
Elza
7 months ago
Hmm, this seems like a straightforward SQL query, but I want to make sure I understand the nuances. The question is asking us to find the person whose name contains the string "John", so I'd say option C is the way to go. The `like '%John%'` syntax allows us to match any name that has "John" anywhere within it.
upvoted 0 times
...

Save Cancel