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Oracle Exam 1Z0-184-25 Topic 1 Question 4 Discussion

Actual exam question for Oracle's 1Z0-184-25 exam
Question #: 4
Topic #: 1
[All 1Z0-184-25 Questions]

You are asked to fetch the top five vectors nearest to a query vector, but only for a specific category of documents. Which query structure should you use?

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Suggested Answer: C

To fetch the top five nearest vectors for a specific category, combine relational filtering (e.g., WHERE category = 'X') with similarity search (C) (e.g., VECTOR_DISTANCE with ORDER BY and FETCH FIRST 5 ROWS). UNION ALL (A) is for combining result sets, not filtering. Omitting WHERE (B) ignores the category constraint. VECTOR_INDEX_HINT (D) influences index usage, not filtering, and skipping WHERE misses the requirement. Oracle's vector search examples use WHERE clauses with similarity functions for such tasks.


Contribute your Thoughts:

Matthew
6 hours ago
Ah, the age-old debate: filters first or similarity search first? I say, why not do both? Just like a good salad, you need the right mix of greens and toppings. Option C all the way!
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Frank
1 days ago
I think C) is the best option because it combines filters with similarity search for more accurate results.
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Willard
2 days ago
I'm not sure, but D) Use VECTOR_INDEX_HINT and NO WHERE clause sounds like it could work too.
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Fidelia
2 days ago
Hold up, did you say 'top five vectors'? I thought we were supposed to fetch the top five documents! This question is getting a bit tricky, isn't it?
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Cherri
5 days ago
Ah, but what if the category of documents is really specific? Using a WHERE clause might be too restrictive. I'd go with option D and use the VECTOR_INDEX_HINT to get the top results without any filters.
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Shaun
5 days ago
I agree with Judy, using relational filters will help narrow down the search.
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Willow
6 days ago
Hmm, I'm not sure about that. Wouldn't it be better to do the similarity search first and then apply the filters? That way, we can focus the search on the most relevant documents.
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Judy
12 days ago
I think we should use C) Apply relational filters and a similarity search in the query.
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Malcom
14 days ago
I think option C is the way to go. Applying the relational filters first and then doing the similarity search seems like the most efficient approach.
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