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NFPA Exam CWBSP Topic 1 Question 8 Discussion

Actual exam question for NFPA's CWBSP exam
Question #: 8
Topic #: 1
[All CWBSP Questions]

How much pressure is lost to friction as 1,200 gpm (4542 L/min) travels through 200 ft (61 m) of 5 in. (130 mm) schedule 40 steel pipe with a C-factor of 120?

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Suggested Answer: C

The pressure loss due to friction for 1,200 gpm traveling through 200 ft of 5 in. schedule 40 steel pipe with a C-factor of 120 is approximately 21 psi (1.45 bar). This calculation takes into account the flow rate, pipe length, diameter, and roughness factor.


Contribute your Thoughts:

Ressie
4 days ago
But the C-factor is high, so it should be A) 28 psi.
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Yvonne
5 days ago
I disagree, I believe it's B) 24 psi.
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Ressie
11 days ago
I think the answer is A) 28 psi.
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Sharen
11 days ago
Hmm, let me see. Okay, I've got it - C) 21 psi (1.45 bar). Friction, you can't live with it, can't live without it.
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Anika
12 days ago
D) 19 psi (1.31 bar). It's all about that pipe roughness, baby! C-factor of 120, no doubt.
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Wei
13 days ago
I'm pretty sure it's B. 24 psi (1.65 bar). Friction is the bane of every hydraulic system, am I right?
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