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NABP Exam NAPLEX Topic 9 Question 79 Discussion

Actual exam question for NABP's NAPLEX exam
Question #: 79
Topic #: 9
[All NAPLEX Questions]

What is the amount of potassium permanganate in 300mL of a 1 in 25 solution?

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Suggested Answer: C

We have 1g of potassium permanganate in 25mL We have 300mL of solution

For every 25mL of that 300mL, we have 1g of KmnO4

300mL must have 12g of potassium permanganate (300ml/25mL)


Contribute your Thoughts:

Shawnda
9 months ago
I would go with 8 grams as well, it seems like the most reasonable option given the dilution.
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Diego
10 months ago
I'm not sure, but I think it might be 12 grams based on the volume of the solution.
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Albina
11 months ago
I agree with A, the concentration of potassium permanganate in the solution is lower so it should be less than 14 grams.
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Terina
11 months ago
I think it's 8 grams because of the dilution factor in the solution.
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Carlee
11 months ago
Well, I'm pretty sure it's 4 grams.
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Yuette
11 months ago
No, I believe it's 8 grams.
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Lanie
11 months ago
I think it's Carlee grams.
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Carlee
11 months ago
Hey, do you know the answer to the potassium permanganate question?
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