NABP Exam NAPLEX Topic 6 Question 98 Discussion

Actual exam question for NABP's NAPLEX exam

Question #: 98
Topic #: 6

[All NAPLEX Questions]

What is the amount of potassium permanganate in 300mL of a 1 in 25 solution?

A1 gram

B8 grams

C12 grams

D14 grams

Show Suggested Answer

Suggested Answer: C

We have 1g of potassium permanganate in 25mL We have 300mL of solution

For every 25mL of that 300mL, we have 1g of KmnO4

300mL must have 12g of potassium permanganate (300ml/25mL)

by Kathrine at Dec 04, 2024, 06:50 PM

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Denny

3 months ago

I calculated it to be 12 grams as well. The concentration of the solution is 1 in 25, so the amount of potassium permanganate would be 1/25 * 300mL = 12 grams.

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Melynda

3 months ago

I'm not sure, but I think it might be 14 grams.

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Felice

3 months ago

12 grams, huh? Sounds about right. I bet the person who got this question right is a wizard at chemistry. Or maybe they just googled the answer. Either way, I'm impressed!

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Werner

2 months ago

Definitely a chemistry wizard!

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Adelina

2 months ago

Yeah, I remember learning about this in chemistry class.

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Gracia

2 months ago

Wow, you're right! That's impressive.

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Nichelle

2 months ago

I think it's C) 12 grams

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Jodi

3 months ago

D) 14 grams

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Tegan

3 months ago

C) 12 grams

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Corazon

3 months ago

B) 8 grams

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Lawana

3 months ago

A) 1 gram

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Cordell

3 months ago

I believe it's 8 grams.

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Richelle

4 months ago

Ooh, 8 grams? That's a lot of potassium permanganate! I wonder if the person who wrote this question has been snacking on some forbidden chemical treats.

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