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Microsoft AZ-700 Exam - Topic 2 Question 36 Discussion

Actual exam question for Microsoft's AZ-700 exam
Question #: 36
Topic #: 2
[All AZ-700 Questions]

SIMULATION

Task 9

You need to ensure that subnet4-3 can accommodate 507 hosts.

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Suggested Answer: A, D

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Meaghan
4 months ago
I thought /23 only covered 512 addresses, not 507.
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Maybelle
5 months ago
Yup, /23 is the way to go!
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Broderick
5 months ago
Wait, are we sure about the subnet size? Seems off.
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Shad
5 months ago
Totally agree, that gives us 510 usable IPs.
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Micaela
5 months ago
Subnetting for 507 hosts needs a /23 mask.
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Letha
5 months ago
I feel like I should double-check the powers of 2 for the subnetting. I know 512 is 2^9, but does that mean we need a /23 mask?
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Viki
5 months ago
This reminds me of a practice question where we had to find the subnet for 300 hosts. I think we used a /23 subnet for that one.
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Valentin
5 months ago
I’m a bit unsure about the exact number of bits we need for the hosts. Was it 9 bits for 512 hosts? I hope I’m remembering that right.
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Sabra
5 months ago
I think we need to calculate the subnet mask that can support at least 507 hosts. I remember something about using the formula 2^n - 2.
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Willow
6 months ago
Journey Builder seems like a good option, as it can help you create personalized customer journeys that incorporate data from multiple Salesforce clouds.
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Zana
6 months ago
I remember practicing questions similar to this, and I think I leaned towards option A, but I'm not totally sure if "comprehensive view" fits the definition we're looking for.
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Paris
6 months ago
SHA might also work, but I'm not as confident that it can fully prevent those types of attacks. I'm leaning towards C.
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Emiko
10 months ago
Hey, at least it's not asking about 666 hosts. That would just be asking for trouble.
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Edda
10 months ago
507 hosts, huh? That's like the number of times I've re-read the question to make sure I'm not missing something obvious.
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Odette
9 months ago
Great job! Make sure to update the subnet mask and address range accordingly.
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Blair
9 months ago
Yes, I calculated that subnet4-3 needs at least a /23 subnet mask to accommodate 507 hosts.
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Kristine
9 months ago
Have you checked the subnet mask and calculated the number of available host addresses?
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Paz
9 months ago
I know, it can be tricky to make sure you're understanding the requirements correctly.
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Essie
10 months ago
I bet the answer is just 'see the explanation' because the exam writer got tired of coming up with creative multiple-choice options.
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Mozell
10 months ago
Alright, let's see what the explanation has. I'm sure it'll be straightforward and not at all convoluted.
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Portia
9 months ago
User3: I'm sure we can figure it out together if it's confusing.
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Dahlia
9 months ago
User2: Let's check it out and see if we can make sense of it.
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Shoshana
9 months ago
User 3: I'm sure it will be helpful.
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Deandrea
10 months ago
User1: I hope the explanation is clear and easy to follow.
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Samuel
10 months ago
User 2: I hope it's easy to follow.
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Huey
10 months ago
User 1: Let's check out the explanation for subnet4-3.
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Rupert
11 months ago
Wait, 507 hosts? That's oddly specific. Is the exam question trying to trick us?
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Staci
10 months ago
User 3: Let's follow the instructions and see how we can accommodate that many hosts.
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Kenneth
10 months ago
User 2: Maybe they want to see if we can calculate the subnet size accurately.
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Lemuel
10 months ago
User 1: I know, 507 hosts seems like a random number.
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Elfrieda
11 months ago
Yes, we should also consider the network and broadcast addresses in our calculation.
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Elly
11 months ago
I think we need to calculate the number of host bits needed for 507 hosts.
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Elfrieda
12 months ago
How do we ensure subnet4-3 can accommodate 507 hosts?
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