E is definitely wrong. If the volume is already associated with a running container, the second command should just attach to that container, not fail.
D sounds plausible, but I'm not sure why the original container image data would be available in both containers. Hmm, I'll have to think this through a bit more.
I think the correct answer is C. Both containers share the contents of the data volume, have full permissions to alter its content and mutually see their respective changes.
Chan
2 months agoLasandra
2 months agoCatarina
2 months agoTerrilyn
29 days agoArt
1 months agoJose
2 months agoElliott
2 months agoMona
2 months agoMabelle
3 months agoLashaunda
3 months agoLisandra
2 months agoRaul
2 months agoTonette
2 months agoRose
2 months agoAhmed
2 months agoQuentin
2 months agoHollis
2 months agoMona
3 months ago