Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions

Huawei Exam H12-891_V1.0 Topic 5 Question 58 Discussion

Actual exam question for Huawei's H12-891_V1.0 exam
Question #: 58
Topic #: 5
[All H12-891_V1.0 Questions]

In the laboratory network, the network is built according to the following topology diagram, SWI is the default configuration, and SW2 disables the switch STP function.

Show Suggested Answer Hide Answer
Suggested Answer: D

Contribute your Thoughts:

Audrie
1 months ago
I'm going with C. It's the only option that makes sense given the information provided. Though I'm still trying to figure out why someone would disable STP in the first place.
upvoted 0 times
Carman
8 days ago
Maybe they disabled STP for a specific reason. It's not common practice, but there could be a valid reason for it.
upvoted 0 times
...
Evelynn
21 days ago
I think C is the correct answer too. It seems like SW2 G0/0/2 would enter the Discarding state if STP is disabled.
upvoted 0 times
...
...
Lucille
1 months ago
Haha, this reminds me of that time I accidentally disabled STP on our production switch. Let's just say the network went down faster than a lead balloon.
upvoted 0 times
Deeanna
16 days ago
Lesson learned, always double check before making changes.
upvoted 0 times
...
Wilson
17 days ago
Did you manage to quickly fix the issue?
upvoted 0 times
...
Alex
23 days ago
I can only imagine the chaos that ensued.
upvoted 0 times
...
Miss
26 days ago
Oh no, that must have been a nightmare!
upvoted 0 times
...
...
Johanna
2 months ago
I believe the correct answer is E) SWI's G0/0/1 enters the Discarding state.
upvoted 0 times
...
Lisbeth
2 months ago
I agree with Lai, because SW2 disables the switch STP function.
upvoted 0 times
...
Lai
2 months ago
I think the answer is A) SG0/0/2 for WI enters the Discarding state.
upvoted 0 times
...
Felicitas
2 months ago
I think the question is trying to trick us. The way the topology is described, it seems like SWI would be the one entering the discarding state, not SW2.
upvoted 0 times
Sage
1 months ago
I'm not sure, let's review the diagram again.
upvoted 0 times
...
Azzie
1 months ago
But what about option A, SG0/0/2 for WI enters the Discarding state?
upvoted 0 times
...
Vinnie
1 months ago
I think option E is correct, SWI's G0/0/1 enters the Discarding state.
upvoted 0 times
...
Rasheeda
2 months ago
I agree, it does seem like a trick question.
upvoted 0 times
...
...
Ellen
2 months ago
The correct answer is C. SW2's G0/0/2 enters the discarding state when the switch STP function is disabled.
upvoted 0 times
Harrison
29 days ago
Oh, I see. Thanks for clarifying!
upvoted 0 times
...
Richelle
1 months ago
Actually, the correct answer is C) SW2 G0/0/2 enters discarding state
upvoted 0 times
...
Fausto
1 months ago
No, I believe it is B) SW2 and G0/0/1 enters the Discarding state
upvoted 0 times
...
Detra
1 months ago
I think the correct answer is A) SG0/0/2 for WI enters the Discarding state
upvoted 0 times
...
...

Save Cancel