Exin Exam CDCS Topic 3 Question 3 Discussion

Actual exam question for Exin's CDCS exam

Question #: 3
Topic #: 3

[All CDCS Questions]

What is the calculation for the desired attenuation factor for shielding material?

AA = 20 log (M / R)
Where
A is Attenuation
M is the maximum acceptable value
R is the real value measured

BA = M / R
Where

BA is Attenuation
M is the maximum acceptable value
R is the real value measured

CA = 20 log (R / M)
Where
A is Attenuation
R is the real value measured
M is the maximum acceptable value

DYou do not have to calculate the attenuation factor for shielding material as it always has the same attenuation

Show Suggested Answer

Suggested Answer: C

The attenuation factor for shielding material is typically calculated using the formula A = 20 log (R / M). This equation provides the attenuation in decibels (dB), where R represents the measured electromagnetic field strength, and M is the maximum acceptable level. The logarithmic scale helps quantify how much the shielding reduces EMF levels relative to the maximum allowable value.

Detailed Explanation:

This formula calculates attenuation by comparing the measured value with the acceptable threshold, with the result expressed in decibels. A higher attenuation indicates more effective shielding material, essential for environments requiring robust EMF management.

EPI Data Center Specialist References:

EPI standards include the use of logarithmic formulas to evaluate attenuation levels, ensuring that shielding materials provide adequate reduction in EMF to protect sensitive equipment within data centers.

by Ma at Oct 18, 2024, 10:20 PM

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Sue

3 months ago

Haha, Option D reminds me of that time my professor said shielding just 'magically' works. Yeah, right!

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4 months ago

Option A seems logical, but I'm not sure why we're using logarithms here. Shouldn't it be a simple ratio?

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Wenona

3 months ago

User 3: Wenona is correct. The calculation involves logarithms to determine the attenuation factor for shielding material.

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Corinne

3 months ago

User 2: Option A: A = 20 log (M / R) where A is Attenuation, M is the maximum acceptable value, and R is the real value measured.

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Malcom

3 months ago

User 1: Option A seems logical, but I'm not sure why we're using logarithms here. Shouldn't it be a simple ratio?

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Misty

4 months ago

I disagree, I believe the correct calculation is A = 20 log (R / M) because it makes more sense in terms of real value measured

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Rima

4 months ago

I think the calculation for the desired attenuation factor is A = 20 log (M / R)

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