Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions
Mail Us support@pass4success.com
Location US
Mob_nav_barsMENU

Exin Exam CDCS Topic 3 Question 3 Discussion

Actual exam question for Exin's CDCS exam
Question #: 3
Topic #: 3
[All CDCS Questions]

What is the calculation for the desired attenuation factor for shielding material?

Show Suggested Answer Hide Answer
Suggested Answer: C

The attenuation factor for shielding material is typically calculated using the formula A = 20 log (R / M). This equation provides the attenuation in decibels (dB), where R represents the measured electromagnetic field strength, and M is the maximum acceptable level. The logarithmic scale helps quantify how much the shielding reduces EMF levels relative to the maximum allowable value.

Detailed Explanation:

This formula calculates attenuation by comparing the measured value with the acceptable threshold, with the result expressed in decibels. A higher attenuation indicates more effective shielding material, essential for environments requiring robust EMF management.

EPI Data Center Specialist References:

EPI standards include the use of logarithmic formulas to evaluate attenuation levels, ensuring that shielding materials provide adequate reduction in EMF to protect sensitive equipment within data centers.


by Ma at Oct 18, 2024, 10:20 PM

Limited Time Offer

25%

Off

Get Premium CDCS Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel
Sue
7 months ago
Haha, Option D reminds me of that time my professor said shielding just 'magically' works. Yeah, right!
upvoted 0 times
...
Odette
8 months ago
The formula in Option A looks like it's trying to be fancy, but Option C is the straightforward way to do it.
upvoted 0 times
Stephaine
6 months ago
Yeah, Option C is definitely the way to go for calculating the desired attenuation factor.
upvoted 0 times
...
Ozell
7 months ago
I think I'll go with Option C for calculating the attenuation factor.
upvoted 0 times
...
Ruthann
7 months ago
I agree, Option C is much simpler and easier to understand.
upvoted 0 times
...
Jaleesa
7 months ago
True, but for practical purposes, Option C should work just fine.
upvoted 0 times
...
Gayla
7 months ago
Option A seems a bit complicated, but it's just a matter of using the right formula.
upvoted 0 times
...
Margart
7 months ago
I think Option A is more accurate though, it takes into account the logarithmic scale.
upvoted 0 times
...
Nida
7 months ago
I agree, Option C is much easier to understand and use.
upvoted 0 times
...
Dallas
7 months ago
Option A seems a bit complicated, I prefer the simplicity of Option C.
upvoted 0 times
...
...
Caprice
8 months ago
Option D is just silly. Of course we have to calculate the attenuation factor! How else would we know if the shielding is effective?
upvoted 0 times
...
Kimi
8 months ago
I remember learning this formula in my EMI shielding class. Option C is the correct one, for sure.
upvoted 0 times
...
Sherill
8 months ago
Option A seems logical, but I'm not sure why we're using logarithms here. Shouldn't it be a simple ratio?
upvoted 0 times
Wenona
7 months ago
User 3: Wenona is correct. The calculation involves logarithms to determine the attenuation factor for shielding material.
upvoted 0 times
...
Corinne
7 months ago
User 2: Option A: A = 20 log (M / R) where A is Attenuation, M is the maximum acceptable value, and R is the real value measured.
upvoted 0 times
...
Malcom
8 months ago
User 1: Option A seems logical, but I'm not sure why we're using logarithms here. Shouldn't it be a simple ratio?
upvoted 0 times
...
...
Misty
8 months ago
I disagree, I believe the correct calculation is A = 20 log (R / M) because it makes more sense in terms of real value measured
upvoted 0 times
...
Rima
8 months ago
I think the calculation for the desired attenuation factor is A = 20 log (M / R)
upvoted 0 times
...

Save Cancel