Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions
Mail Us support@pass4success.com
Location US
Mob_nav_barsMENU

Databricks Exam Databricks-Certified-Professional-Data-Scientist Topic 3 Question 56 Discussion

Actual exam question for Databricks's Databricks-Certified-Professional-Data-Scientist exam
Question #: 56
Topic #: 3
[All Databricks-Certified-Professional-Data-Scientist Questions]

Suppose there are three events then which formula must always be equal to P(E1|E2,E3)?

Show Suggested Answer Hide Answer
Suggested Answer: B

by Kerry at Apr 13, 2024, 02:36 AM

Limited Time Offer

25%

Off

Get Premium Databricks-Certified-Professional-Data-Scientist Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel
Virgilio
9 months ago
I think the answer is C) P(E1,E2|E3)P(E2|E3)P(E3), as it involves all three events E1, E2, and E3
upvoted 0 times
...
Kris
9 months ago
I believe the formula should be P(E1,E2,E3)/P(E2,E3) to calculate P(E1|E2,E3)
upvoted 0 times
...
Micheal
9 months ago
I agree with Diane, P(E1|E2) = P(E1,E2)/P(E2) is the correct formula for conditional probability
upvoted 0 times
...
Diane
9 months ago
I think the formula that must always be equal to P(E1|E2,E3) is P(E1|E2) = P(E1,E2)/P(E2)
upvoted 0 times
...
Meghann
10 months ago
So the formula is essentially P(E1,E2|E3)P(E2|E3)P(E3)
upvoted 0 times
...
Ceola
10 months ago
I agree, it involves conditional probability calculation
upvoted 0 times
...
Nicolette
11 months ago
I think it's C) P(E1,E2|E3)P(E2|E3)P(E3)
upvoted 0 times
...
Dannie
11 months ago
What formula must always be equal to P(E1|E2,E3)?
upvoted 0 times
...
Paz
11 months ago
Absolutely. And you know what they say, 'practice makes perfect!' We're gonna ace this exam, guys.
upvoted 0 times
...
Katie
11 months ago
Haha, I bet the exam writers thought they were being really clever with this one. But now that we've worked it out, it doesn't seem too bad. Just gotta remember that conditional probability formula, right?
upvoted 0 times
...
Novella
12 months ago
Ooh, I see! That makes sense. The other options don't seem to capture the right relationship between the events. Nice catch!
upvoted 0 times
...
Oliva
12 months ago
Yeah, you're right. The formula we want is P(E1,E2,E3)/P(E2,E3), which is option B. This gives us the probability of E1 occurring, given that E2 and E3 have also occurred.
upvoted 0 times
...
Karl
12 months ago
Okay, let's think this through step-by-step. We have three events, E1, E2, and E3, and we're supposed to find a formula that's always equal to P(E1|E2,E3). Hmm, I think the key here is to use the definition of conditional probability.
upvoted 0 times
Kanisha
10 months ago
So basically, we need to manipulate the probabilities of E1, E2, and E3 to find the correct conditional probability
upvoted 0 times
...
Jodi
10 months ago
Right, we can use the formula P(E1,E2)=P(E1|E2)P(E2) to calculate conditional probability
upvoted 0 times
...
Kenneth
10 months ago
The formula that must always be equal to P(E1|E2,E3) is C) P(E1,E2|E3)P(E2|E3)P(E3)
upvoted 0 times
...
...
Precious
12 months ago
Wow, this conditional probability question looks quite tricky. I'm not sure I fully understand the relationship between the different events and the formula we're supposed to use.
upvoted 0 times
...

Save Cancel