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Databricks Exam Databricks-Certified-Data-Analyst-Associate Topic 3 Question 28 Discussion

Actual exam question for Databricks's Databricks-Certified-Data-Analyst-Associate exam
Question #: 28
Topic #: 3
[All Databricks-Certified-Data-Analyst-Associate Questions]

A data analyst has created a user-defined function using the following line of code:

CREATE FUNCTION price(spend DOUBLE, units DOUBLE)

RETURNS DOUBLE

RETURN spend / units;

Which of the following code blocks can be used to apply this function to the customer_spend and customer_units columns of the table customer_summary to create column customer_price?

Show Suggested Answer Hide Answer
Suggested Answer: E

A user-defined function (UDF) is a function defined by a user, allowing custom logic to be reused in the user environment1.To apply a UDF to a table, the syntax isSELECT udf_name(column_name) AS alias FROM table_name2. Therefore, option E is the correct way to use the UDFpriceto create a new columncustomer_pricebased on the existing columnscustomer_spendandcustomer_unitsfrom the tablecustomer_summary.Reference:

What are user-defined functions (UDFs)?

User-defined scalar functions - SQL

V


by Selma at Oct 23, 2024, 12:49 AM

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Mirta
11 days ago
D is interesting, but I don't think we need to explicitly cast the result as a double. E is the clearest choice in my opinion.
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Carrol
15 days ago
I agree with Graciela, option E looks like the right choice because it directly applies the function to the columns.
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Bok
16 days ago
Hmm, I'm not sure about option C. Wrapping the function call in another function call seems unnecessary.
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Thea
3 days ago
E) SELECT price(customer_spend, customer_units) AS customer_price FROM customer_summary
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Luz
5 days ago
A) SELECT PRICE customer_spend, customer_units AS customer_price FROM customer_summary
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Fallon
19 days ago
Option E looks good to me. Applying the custom function directly to the columns is the straightforward way to do it.
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Tijuana
1 days ago
I think option E is the correct choice as well. It makes sense to use the function directly on the columns.
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Stefania
12 days ago
Option E looks good to me. Applying the custom function directly to the columns is the straightforward way to do it.
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Graciela
27 days ago
I think the correct answer is E.
upvoted 0 times
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