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Databricks Exam Databricks-Certified-Associate-Developer-for-Apache-Spark-3.0 Topic 2 Question 46 Discussion

Actual exam question for Databricks's Databricks-Certified-Associate-Developer-for-Apache-Spark-3.0 exam
Question #: 46
Topic #: 2
[All Databricks-Certified-Associate-Developer-for-Apache-Spark-3.0 Questions]

Which of the following code blocks returns the number of unique values in column storeId of DataFrame transactionsDf?

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Suggested Answer: A

transactionsDf.select('storeId').dropDuplicates().count()

Correct! After dropping all duplicates from column storeId, the remaining rows get counted, representing the number of unique values in the column.

transactionsDf.select(count('storeId')).dropDuplicates()

No. transactionsDf.select(count('storeId')) just returns a single-row DataFrame showing the number of non-null rows. dropDuplicates() does not have any effect in this context.

transactionsDf.dropDuplicates().agg(count('storeId'))

Incorrect. While transactionsDf.dropDuplicates() removes duplicate rows from transactionsDf, it does not do so taking only column storeId into consideration, but eliminates full row duplicates

instead.

transactionsDf.distinct().select('storeId').count()

Wrong. transactionsDf.distinct() identifies unique rows across all columns, but not only unique rows with respect to column storeId. This may leave duplicate values in the column, making the count

not represent the number of unique values in that column.

transactionsDf.select(distinct('storeId')).count()

False. There is no distinct method in pyspark.sql.functions.


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