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CIW Exam 1D0-735 Topic 4 Question 69 Discussion

Actual exam question for CIW's 1D0-735 exam
Question #: 69
Topic #: 4
[All 1D0-735 Questions]

Consider the following code:

What change should be made to ensure that it correctly displays the value of name in all uppercase letters?

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Suggested Answer: B

by Dante at Sep 13, 2024, 04:00 AM

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Annelle
2 months ago
I'm cracking up at the typo in Option D. 'sting' instead of 'string'? Somebody needs to proofread these exam questions!
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William
25 days ago
User 3: Definitely, that typo could confuse someone during the exam.
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Kati
1 months ago
User 2: I know right, they really need to proofread these questions better.
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Monroe
2 months ago
User 1: Option D is hilarious, 'sting' instead of 'string'!
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Alana
2 months ago
Option C looks promising, but I'm not sure if document.write() is the best way to display the value. Might be better to use innerHTML or textContent.
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Rashad
1 months ago
Option C looks promising, but I'm not sure if document.write() is the best way to display the value. Might be better to use innerHTML or textContent.
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Marlon
2 months ago
B) Line 2 should be changed to name .prototype . toUpperCase () ;
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Lynette
2 months ago
A) Line 2 should be changed to name = name . toUpperCase () ;
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Meghan
2 months ago
Haha, Option B is clearly a joke. Why would we need to call toUpperCase() on the prototype? That's just silly.
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Selma
1 months ago
Kimberlie: I think so too, calling toUpperCase() directly on the string variable makes more sense.
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Yesenia
1 months ago
User 3: Option A seems like the correct answer to me.
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Kimberlie
2 months ago
User 2: Yeah, it's definitely not the right choice.
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Tasia
2 months ago
User 1: I agree, Option B doesn't make any sense.
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Alecia
3 months ago
I think Option D is the way to go. We need to create a new String object to ensure the name is properly defined.
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Sena
1 months ago
User 2: Line 1 should be changed to var name = new String(\'Jaccb\').
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Micah
2 months ago
User 1: I think Option D is the way to go. We need to create a new String object to ensure the name is properly defined.
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Tanja
3 months ago
Option A is the correct answer. We need to call the toUpperCase() method on the name variable to convert it to uppercase.
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Daisy
3 months ago
I'm not sure, but I think the answer might be C.
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Lyndia
3 months ago
I disagree, I believe the correct answer is B.
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Marsha
3 months ago
I think the answer is A.
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