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C++ Institute CPP Exam - Topic 7 Question 78 Discussion

Actual exam question for C++ Institute's CPP exam
Question #: 78
Topic #: 7
[All CPP Questions]

What happens when you attempt to compile and run the following code?

#include

#include

using namespace std;

int main() {

int t[] = { 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };

string s[] = { "one", "one", "two", "two", "three","three", "four", "four", "five", "five"};

multimap m;

for (int i = 0; i < 10; i++) {

m.insert(pair(t[i], s[i]));

}

if (m.count(3) == 2) {

m.erase(3);

}

for (multimap::iterator i = m.begin(); i != m.end(); i++) {

cout << i?>first << " ";

}

return 0;

}

Show Suggested Answer Hide Answer
Suggested Answer: D

Contribute your Thoughts:

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Clarinda
3 months ago
I agree with the output being 1 1 2 2 4 4 5 5!
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Sheridan
3 months ago
Wait, are you sure it doesn't include 3 at all?
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Dorothy
4 months ago
Definitely outputs 1 1 2 2 4 4 5 5!
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Carmelina
4 months ago
I think it should be 1 2 4 5 instead.
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Therese
4 months ago
The program will output 1 1 2 2 4 4 5 5.
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Samira
4 months ago
I think the output should exclude the 3, but I'm confused about whether it will still show the duplicates for other numbers.
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Therese
5 months ago
This seems similar to a practice question we did, but I can't recall if it was about counting or erasing.
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Cordelia
5 months ago
I’m not sure, but I think the erase function will remove all entries with the key 3, right?
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Scot
5 months ago
I remember that multimap allows duplicate keys, so the count function should return 2 for key 3.
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Kati
5 months ago
I'm not sure I fully understand what's happening with the erase operation on the multimap. I'll need to walk through it carefully to make sure I get the right answer.
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Javier
5 months ago
I'm feeling pretty confident about this one. The output should be the unique keys in the multimap after the erase operation, which is 1, 2, 4, 5.
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Glory
5 months ago
Okay, I think I've got this. The key is understanding how the multimap stores duplicate keys and how the erase operation removes all instances of a given key.
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Gracia
5 months ago
Hmm, I'm a bit confused by the use of the multimap here. I'll need to review how that data structure works and how the insert and erase operations affect the output.
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Lorrie
5 months ago
This looks like a tricky one. I'll need to carefully step through the code and think about how the multimap is being used.
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Lynelle
5 months ago
Ah, I've seen these types of questions before. The key is to focus on the details in the URIs and match them to the threat kill chain stages. I'm confident I can get this one right.
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Aide
5 months ago
This is a tricky one. I'm leaning towards option D, using a custom script to convert the nulls. That way I can make sure I'm handling them exactly as the question specifies, without potentially messing up the data format. It might take a bit more work, but I think it's the safest approach.
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Laticia
5 months ago
Hmm, I'm a little unsure about this one. I'll have to think it through carefully before answering.
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Noel
5 months ago
Okay, let's see here. The key seems to be understanding how the backup process is supposed to work and what could be causing the failure. I'll need to consider each of the answer choices carefully.
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Matthew
5 months ago
Okay, I've got this. Option B is the clear winner here. Listening to the views of a wide range of employees, including those on the factory floor, shows real respect for people at all levels of the organization. That's exactly the kind of behavior the question is looking for.
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Raina
5 months ago
I'm a bit confused here, I feel like I've seen a question about AES using a 168-bit key, but that doesn't seem right.
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Arlette
2 years ago
I agree with Eleonore, I think the answer is: 1 2 4 5 because the program removes one occurrence of value 3.
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Eleonore
2 years ago
I'm not so sure, but I think the output could be: 1 2 4 5 since the value 3 is erased from the multimap.
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Joanna
2 years ago
I believe the correct output is: 1 2 3 4 5 because there are 2 occurrences of value 3 in the multimap.
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Ettie
2 years ago
I think the program might output: 1 2 3 4 5.
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