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C++ Institute Exam CPP Topic 6 Question 104 Discussion

Actual exam question for C++ Institute's CPP exam
Question #: 104
Topic #: 6
[All CPP Questions]

What happens when you attempt to compile and run the following code?

#include

#include

int main ()

{

int t[]={1,2,3,4,5};

std::vectorv1(t,t+5);

std::vectorv2(v1);

v1.resize(10);

v2.reserve(10);

std::vector::iterator i = v1.begin();int ii = 0;

while (i != v1.end()) { std::cout<

i = v2.begin();ii=0;

while (i != v2.end()) { std::cout<

return 0;

}

Show Suggested Answer Hide Answer
Suggested Answer: E

Contribute your Thoughts:

Trina
1 days ago
Ah, the classic vector resizing and copying conundrum. I bet the answer has something to do with the difference between resize() and reserve().
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Micaela
7 days ago
This looks like a tricky one! I'm going to have to think through the memory management implications carefully.
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Beth
9 days ago
I'm not sure, but I think the answer might be C) program outputs 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5 because of the way the vectors are being manipulated.
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Andrew
10 days ago
I agree with Goldie, the code looks like it will not compile correctly.
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Goldie
14 days ago
I think the answer is B) compilation error because there seems to be an issue with the code.
upvoted 0 times
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