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C++ Institute CPP Exam - Topic 6 Question 104 Discussion

What happens when you attempt to compile and run the following code?#include #include int main (){int t[]={1,2,3,4,5};std::vectorv1(t,t+5);std::vectorv2(v1);v1.resize(10);v2.reserve(10);std::vector::iterator i = v1.begin();int ii = 0;while (i != v1.end()) { std::cout
A) program outputs 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
B) compilation error
C) program outputs 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5
D) program outputs 1 2 3 4 5 0 0 0 0 0 1 2 3 4 5 0 0 0 0 0

C++ Institute CPP Exam - Topic 6 Question 104 Discussion

Actual exam question for C++ Institute's CPP exam
Question #: 104
Topic #: 6
[All CPP Questions]

What happens when you attempt to compile and run the following code?

#include

#include

int main ()

{

int t[]={1,2,3,4,5};

std::vectorv1(t,t+5);

std::vectorv2(v1);

v1.resize(10);

v2.reserve(10);

std::vector::iterator i = v1.begin();int ii = 0;

while (i != v1.end()) { std::cout<

i = v2.begin();ii=0;

while (i != v2.end()) { std::cout<

return 0;

}

Show Suggested Answer Hide Answer
Suggested Answer: E

Contribute your Thoughts:

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Altha
9 months ago
I agree, D seems like the most likely output here.
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Merilyn
9 months ago
Wait, why would it output so many 1s? That seems off.
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Tenesha
9 months ago
Definitely not a compilation error.
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Altha
10 months ago
I think the output will be a mix of 1s and 0s.
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Curtis
10 months ago
Looks like it should compile fine.
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Lachelle
10 months ago
I feel like the program will just print a bunch of ones because of how the iterator is being used, but I could be wrong.
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Ria
10 months ago
The output might be a mix of the original array and zeros, but I can't recall exactly how the resizing affects the output.
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Brett
10 months ago
I remember something similar where using an uninitialized index caused issues. I wonder if that's what's happening here with "ii??".
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Elvis
11 months ago
I think the code should compile fine since it uses standard vector operations, but I'm not sure about the iterator part.
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Vivan
11 months ago
I've seen similar questions before, so I think I have a good handle on this. Let me walk through the code and the expected behavior of the vector operations.
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Jarod
11 months ago
I'm not sure about this one. The output doesn't seem straightforward, and I'll need to think it through carefully to determine the correct answer.
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Salena
11 months ago
Okay, I think I've got this. The key is understanding the difference between the capacity and size of the vectors. Let me work through it step-by-step.
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Lisbeth
11 months ago
Hmm, I'm a bit confused about the use of `reserve()` and `resize()` here. I'll need to review how those methods work to figure out the expected output.
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Ardella
11 months ago
This looks like a tricky one. I'll need to carefully step through the code to understand what's happening with the vectors.
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Jose
1 year ago
Wait, is that a typo in the loop? I think the '??' is supposed to be '++'. Gotta pay attention to the small details!
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Artie
1 year ago
B) compilation error
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Rosann
1 year ago
B) compilation error
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Tamesha
1 year ago
B) compilation error
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Alecia
1 year ago
I'm picturing the output being a weird mix of 1s and the original elements. This should be a fun one to work through.
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Christoper
1 year ago
C) program outputs 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5
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Christoper
1 year ago
B) compilation error
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Christoper
1 year ago
A) program outputs 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
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Nichelle
1 year ago
Haha, I can already see the compiler throwing a fit at this code. Time to brush up on my C++ vector knowledge!
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Rosio
1 year ago
I believe the program will output 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5.
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Rosio
1 year ago
Yeah, the code looks like it might have some issues with iterators.
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Rosio
1 year ago
I think it will output a compilation error.
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Trina
1 year ago
Ah, the classic vector resizing and copying conundrum. I bet the answer has something to do with the difference between resize() and reserve().
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Roosevelt
1 year ago
B) compilation error
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Roosevelt
1 year ago
C) program outputs 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5
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Micaela
1 year ago
This looks like a tricky one! I'm going to have to think through the memory management implications carefully.
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Howard
1 year ago
I think it will result in a compilation error
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Howard
1 year ago
No, it will output 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5
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Howard
1 year ago
It will output 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
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Beth
1 year ago
I'm not sure, but I think the answer might be C) program outputs 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5 because of the way the vectors are being manipulated.
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Andrew
1 year ago
I agree with Goldie, the code looks like it will not compile correctly.
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Goldie
1 year ago
I think the answer is B) compilation error because there seems to be an issue with the code.
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