What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main ()
{
int t[] = {1, 2 ,3 ,4 ,5};
vector
list
l1.assign(v1.end(), v1.begin());
for(int i=0; i { cout< } cout< return 0; }
Suggested Answer: C
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20 comments · newest first
AN
Anthony
1 month ago
I thought it might run fine, but now I’m not so sure.
FA
Fabiola
1 month ago
I’m leaning towards option C too. It just doesn’t make sense.
MY
My
2 months ago
No way, it won't compile. Line 8 is definitely an issue.
LE
Levi
2 months ago
I feel like it should output 5 4 3 2 1.
GL
Gladys
2 months ago
Yeah, I agree. The order of parameters in assign is wrong.
LO
Lorrine
2 months ago
I think it will give a compilation error in line 8.
CA
Cassi
2 months ago
I think it's a runtime exception, not a compilation error.
LE
Leonardo
2 months ago
Nope, it outputs 1 2 3 4 5 if it compiles!
TA
Taryn
3 months ago
Wait, really? I thought it would just print the numbers.
AL
Aliza
3 months ago
Totally agree, you can't use `at()` on a list!
LA
Lawanda
3 months ago
The program will actually have a compilation error in line 8.
FE
Fernanda
3 months ago
I think it's option C for sure.
GA
Gary
3 months ago
Nope, it outputs nothing because of that error.
BL
Blythe
3 months ago
Wait, really? I thought it would just output the numbers.
CR
Crista
5 months ago
Totally agree, you can't use `at()` on a list!
JO
Jordan
5 months ago
The code will actually cause a compilation error in line 8.
LO
Lourdes
6 months ago
I think the loop on line 8 could cause a runtime error since `l1.size()` might not work as expected with a list.
KR
Krystal
6 months ago
I feel like there might be a compilation error because of the way `l1.assign` is used. It seems like the parameters are in the wrong order.
JA
Jamika
6 months ago
I remember practicing a similar question where we had to use `assign`, but I can't recall if the order of parameters matters.
MI
Mica
6 months ago
I think the code should compile fine, but I'm not sure about the output since the `assign` method seems a bit confusing.