C++ Institute Exam CPA Topic 2 Question 82 Discussion

Actual exam question for C++ Institute's CPA exam

Question #: 82
Topic #: 2

[All CPA Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int main()

{

string s1[]= {"How" , "to" };

s1[0].swap(s1[1]);

for (int i=0; i<2; i++) {

cout << s1[i];

}

return( 0 );

}

AIt prints: Hoto

BIt prints: toHow

CIt prints: Ht

DIt prints: to

Show Suggested Answer

Suggested Answer: B

by Samira at Mar 09, 2024, 07:22 PM

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Herminia

5 months ago

I think the correct answer is A) It prints: Hoto because the swap method is being used on the strings in the array.

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Marnie

5 months ago

I believe it will print 'Hoto' because 'How' is being swapped with 'to'.

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Antione

5 months ago

So, the answer would be either A) It prints: Hoto or B) It prints: toHow.

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Karina

6 months ago

I agree, it looks like it's swapping 'How' and 'to'.

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Walker

6 months ago

I think the code is swapping the positions of the strings in the array.

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Audry

6 months ago

I guess we'll find out the correct answer when we compile and run the code.

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Audry

6 months ago

I'm not sure, but I think it prints: Hoto.

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Janey

7 months ago

Because the swap function swaps the values of the elements, resulting in toHow.

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Herman

7 months ago

But why do you think it would be toHow?

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Janey

7 months ago

I believe it prints: Hoto.

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Herman

7 months ago

I think it prints: toHow.

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