C++ Institute Exam CPA-21-02 Topic 5 Question 28 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 28
Topic #: 5

[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

class complex{

double re;

double im;

public:

complex() : re(1),im(0.4) {}

bool operator==(complex &t);

};

bool complex::operator == (complex &t){

if((this?>re == t.re) && (this?>im == t.im))

return true;

else

return false;

}

int main(){

complex c1,c2;

if (c1==c2)

cout << "OK";

else {

cout << "ERROR";

}

AIt prints: OK

BIt prints: ERROR

CCompilation error

DRuntime error.

Show Suggested Answer

Suggested Answer: A

by Angelyn at Sep 15, 2024, 08:35 PM

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Layla

6 months ago

D, runtime error. I bet the compiler will yell at us for trying to compare complex numbers without overloading the == operator properly. Whoever wrote this code needs to go back to Complex Numbers 101!

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Zona

5 months ago

Definitely a compilation error. The code needs to be fixed before it can run properly.

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Glendora

5 months ago

Yeah, I agree. The code is trying to compare complex numbers without the proper operator overloading.

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Adolph

5 months ago

I think it will print ERROR because the == operator is not properly overloaded for complex numbers.

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Mitsue

6 months ago

I'm not sure, but I think it will print ERROR because the operator== function is not correctly implemented.

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Joni

6 months ago

Easy peasy, the answer is A! The code will print 'OK' because the default constructor sets the values for c1 and c2, and the overloaded == operator compares them correctly.

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Beckie

6 months ago

Hmm, I'm not sure. The code looks a bit complex (no pun intended), but I'll go with C, compilation error. There's something about the overloaded == operator that doesn't look quite right.

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Callie

5 months ago

Looks like we all think it's a compilation error. Let's see if that's the case.

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Wilford

6 months ago

I agree with User1 and User2. The code will not compile due to the missing return type in the overloaded operator.

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Marylou

6 months ago

User1, you're correct. The code will print 'ERROR' because the overloaded == operator is missing a return type.

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Bobbye

6 months ago

It prints: ERROR

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Stevie

7 months ago

I think the answer is B, it prints ERROR. The constructor of the complex class initializes the real part to 1 and the imaginary part to 0.4, so c1 and c2 will not be equal.

upvoted 0 times