C++ Institute Exam CPA-21-02 Topic 5 Question 25 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 25
Topic #: 5

[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int mul (int a, int b=2)

{

int r;

r=a*b;

return (r);

}

int main ()

{

cout << mul(1) << mul(2,4);

return 0;

}

AIt prints: 2

BIt prints: 28

CIt prints: 8

DIt prints: 6

Show Suggested Answer

Suggested Answer: A

by Merissa at Sep 15, 2024, 03:10 PM

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Truman

3 days ago

Wait, wait, wait... I think I got this. The default parameter in 'mul' is 2, so 'mul(1)' will give us 2. And 'mul(2,4)' will give us 8. Putting them together, the answer must be B) It prints: 28. Nailed it!

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Refugia

4 days ago

This is easy! The default parameter in the 'mul' function is 2, so 'mul(1)' will return 2. Then 'mul(2,4)' will return 8. Add them up, and the answer is C) It prints: 8.

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Fatima

5 days ago

Hmm, let's see... if the default value for the second parameter in the 'mul' function is 2, then calling 'mul(1)' should give us 2. And 'mul(2,4)' should give us 8. So the answer must be D) It prints: 6.

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Fairy

11 days ago

But if you look at the code, when mul(1) is called, it uses the default value of b which is 2, so it should be 1*2=2. And when mul(2,4) is called, it should be 2*4=8. So the answer should be B) It prints: 28.

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Merri

13 days ago

I disagree, I believe the answer is C) It prints: 8.

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Fairy

14 days ago

I think the answer is B) It prints: 28.

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