C++ Institute Exam CPA-21-02 Topic 4 Question 19 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 19
Topic #: 4

[All CPA-21-02 Questions]

How many times will "HELLO" be printed?

#include

using namespace std;

int main()

{

for(int i=?1; i<=10; i++)

{

if(i < 5)

continue;

else

break;

cout<<"HELLO";

}

return 0;

}

D20

Show Suggested Answer

Suggested Answer: A, B

by Louis at Jun 29, 2024, 11:50 PM

Limited Time Offer

25%

Off

Get Premium CPA-21-02 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Val

2 months ago

Ah, the age-old battle of off-by-one errors. I bet the exam writer is having a good laugh at our expense right now.

upvoted 0 times

...

Reta

2 months ago

20? Are you kidding me? The loop runs from i=5 to i=10, and 'HELLO' is printed only once. This is clearly a joke answer. I'm going with B as the correct response.

upvoted 0 times

...

Shanice

2 months ago

This is a tricky one! The loop initializes i to some value, but the question doesn't specify what that value is. So, I'm not sure if the loop will even run. I'll go with C as the safest option.

upvoted 0 times

...

Goldie

2 months ago

Wait, what? The loop runs from i=5 to i=10, but the 'else' block with 'break' is executed as soon as i reaches 5. So, 'HELLO' is printed only once. I guess B is the right answer.

upvoted 0 times

Nan

14 days ago

You're right, it will only be printed once.

upvoted 0 times

...

Elina

16 days ago

Oh, I see. So the correct answer is B) 2

upvoted 0 times

...

Detra

17 days ago

No, it's actually B) 2

upvoted 0 times

...

Dorcas

22 days ago

I think the answer is A) 1

upvoted 0 times

...

Derick

26 days ago

No, it will only be printed once.

upvoted 0 times

...

Sonia

1 months ago

I think it will be printed twice.

upvoted 0 times

...

Eliseo

2 months ago

Hmm, let's see. The loop runs from i=5 to i=10, and 'HELLO' is printed in each iteration, so the answer must be 6. Looks like C is the correct choice.

upvoted 0 times