If an object is placed 1 m (3 ft) away from a light source and the lux level is 3200 lux, what is the lux level at a distance of 8 m (24 ft)?
If an object is placed 1 meter (3 feet) away from a light source with a lux level of 3200 lux, the lux level decreases according to the inverse square law of light. At a distance of 8 meters (24 feet), the lux level can be calculated as:
NewLuxLevel=3200lux(8/1)2=3200lux64=50luxtext{New Lux Level} = frac{3200 text{ lux}}{(8/1)^2} = frac{3200 text{ lux}}{64} = 50 text{ lux}NewLuxLevel=(8/1)23200lux=643200lux=50lux
Thus, at 8 meters, the light intensity drops significantly to 50 lux.
Kimberlie
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