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Arista Exam ACE-P-ALE1.04 Topic 2 Question 100 Discussion

Actual exam question for Arista's ACE-P-ALE1.04 exam
Question #: 100
Topic #: 2
[All ACE-P-ALE1.04 Questions]

Which two characters are required at the top of a script to inform the kernel on which interpreter to use? (choose two)

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Suggested Answer: B, D

by Jackie at Sep 14, 2024, 01:40 AM

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Melda
28 days ago
This question is a real 'shell' of a time, isn't it? But seriously, D is the correct answer. #! is the way to 'bash' the kernel into submission.
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Elenora
6 days ago
B) $!
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Dortha
15 days ago
A) !!
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Lina
29 days ago
Hmm, let me think... Ah, yes! #! is the one we want. The shebang is the way to go, no doubt about it.
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Vincent
1 months ago
D, definitely. I'm not even sure what the other options are supposed to be. #! is the standard, everyone knows that!
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Nida
1 months ago
D, of course. #! is the classic way to tell the kernel which interpreter to use. Anything else is just plain wrong.
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Sherly
5 days ago
Definitely, #! is the way to go. It's a standard practice.
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Major
12 days ago
I agree, #! is the correct way to inform the kernel about the interpreter.
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Mona
20 days ago
D, of course. #! is the classic way to tell the kernel which interpreter to use.
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Lashonda
2 months ago
Ah, the age-old question - #! is the one true shebang! All other options are mere impostors.
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Yuki
5 days ago
B) $!
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Carin
6 days ago
I agree, #! is the correct shebang!
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Rosendo
9 days ago
D) #!
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Huey
26 days ago
A) !!
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Candida
2 months ago
I'm not sure, but I think A) !! and D) #! are the correct answers
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Kimberlie
2 months ago
I agree with Susana, because #! is the shebang line that specifies the interpreter
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Susana
2 months ago
I think the answer is D) #!
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