Appian ACD101 Exam - Topic 5 Question 31 Discussion

Actual exam question for Appian's ACD101 exam

Question #: 31
Topic #: 5

[All ACD101 Questions]

Review the following expression rule:

union(ri!fruit, ri!vegetables)

The rule inputs are configured as text arrays.

What is the expected output?

AAll items in ri!fruit followed by items in ri!vegetables, including duplicate values.

BOnly items that are in both ri!fruit and ri!vegetables.

CAll items in ri!fruit and ri!vegetables combined, with duplicates removed.

Show Suggested Answer

Suggested Answer: B

The best practice in Appian for passing values into an interface is to use named parameters, which is demonstrated by Option B. Named parameters make the code more readable and maintainable by clearly specifying which parameter each value is being passed to. In this case, the recordId and firstName parameters are clearly being assigned the values 1 and 'Kyle' respectively. Reference:

Appian Documentation: Passing Parameters to Interfaces

by Arlette at Feb 11, 2025, 08:21 AM

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Harris

3 months ago

Really? I thought it would just give unique items.

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Moon

4 months ago

A is correct, all items included, duplicates and all!

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Mozelle

4 months ago

Wait, are you sure it's not B? That seems off.

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Mitsue

4 months ago

I think it's C, duplicates should be removed.

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Shantay

4 months ago

Definitely A, it combines everything!

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Sol

5 months ago

I feel like I saw something about union in our notes, but I can't recall if it was about keeping duplicates or not.

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Nieves

5 months ago

I’m a bit confused; I thought union would just list everything, including duplicates, like in option A.

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Elly

5 months ago

I remember practicing a similar question where the union removed duplicates, so I might lean towards option C.

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Magdalene

5 months ago

I think the union function combines both arrays, but I'm not sure if it keeps duplicates or not.

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Katie

5 months ago

Alright, I've got it. The rule is taking the items from ri!fruit and ri!vegetables and combining them, but it's not removing any duplicates. So the output should be all the items from both arrays, including any duplicates. That's option A.

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Celestina

5 months ago

I'm a little confused by the wording here. Is the rule actually doing a union operation, or is it just combining the two arrays in some way? I'll need to re-read this a few times to make sure I understand what it's asking for.

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Werner

5 months ago

I think I've got this. The rule is saying "union", so I'm guessing the output will be all the items from both arrays, with any duplicates removed. That sounds like option C to me.

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Delila

5 months ago

Okay, let's see. The rule is taking two text arrays as input, so I'm guessing the output will be some kind of combination of those two arrays. I'll need to pay close attention to the wording to figure out exactly what it's asking for.

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Alishia

5 months ago

Hmm, this looks like a tricky one. I'll need to think it through carefully to make sure I understand the rule correctly.

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Maile

11 months ago

Union? More like 'onion' - this question is making me cry!

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Cherelle

9 months ago

C) All items in ri!fruit and ri!vegetables combined, with duplicates removed.

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Kristian

9 months ago

B) Only items that are in both ri!fruit and ri!vegetables.

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Annalee

9 months ago

A) All items in ri!fruit followed by items in ri!vegetables, including duplicate values.

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Edwin

11 months ago

Hmm, this is a tricky one. I'm leaning towards B, since the question mentions the rule 'union', which might have a different behavior than a regular union operation.

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Zoila

11 months ago

I'm going with C. The union operation should remove any duplicate values, so the output should be a combined list of all items from both arrays, without duplicates.

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Stephaine

9 months ago

C makes sense to me too.

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Sherron

9 months ago

I'm not sure, but C sounds logical.

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Annmarie

9 months ago

I agree, C seems like the right choice.

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Glendora

10 months ago

I think the correct answer is C.

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Kristofer

11 months ago

I'm not sure about this one. The question talks about a 'rule', so I'm guessing the output might be different from a standard union operation. I'll have to think about it some more.

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