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Adobe Exam AD0-E213 Topic 3 Question 41 Discussion

Actual exam question for Adobe's AD0-E213 exam
Question #: 41
Topic #: 3
[All AD0-E213 Questions]

When may the JavaScript exception 'TypeError: "x" is not a function' occur?

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Suggested Answer: C

The JavaScript exception 'TypeError: 'x' is not a function' occurs when the type of the value returned by function V does not match its declared type. For example, if a function is declared to return an integer but returns a string instead, this exception will occur. This can happen when incorrect data types are used or when the function is called with the wrong number of arguments. Reference: https://www.adobe.com/content/dam/acom/en/devnet/analytics/analytics-developer-professional-study-guide.pdf


by Horace at May 23, 2024, 05:00 PM

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Jeannine
9 months ago
Wait, is the function called 'V' or is that just a variable name in the question? I'm so confused right now...
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Elly
9 months ago
I'm going to have to go with B. Seems like the most straightforward way to get that particular error message.
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Salome
9 months ago
Option A sounds plausible, but I'm not sure if that's the only way this error can occur. Maybe it's a trick question!
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Dorcas
8 months ago
C) When the type of the value returned by function V does not match its declared type.
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Louvenia
8 months ago
Maybe it's a combination of both scenarios that can cause that error.
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Viola
8 months ago
B) When function V is called after it is defined.
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Aretha
8 months ago
A) When function V shares its name with a variable define earlier.
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Christoper
8 months ago
I think it could also happen if function V is called before it is defined.
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Lindsey
8 months ago
Option A is a common reason for that error.
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Alpha
9 months ago
Hmm, I'm going with C. If the function is expecting a specific data type and it gets something else, that could definitely cause a TypeError.
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Margurite
8 months ago
I'm not sure, but I think it could also be A. Sharing a name with a variable might cause confusion.
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Elsa
8 months ago
I agree with you, it's definitely B. Calling a function before it's defined can lead to that error.
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Yun
8 months ago
I think it's B. If you call a function before it's defined, that could cause a TypeError.
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Herminia
9 months ago
I think it's option B. Calling a function before it's defined seems like a common way to trigger that error.
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Annmarie
8 months ago
I think it's option C. The type of the value returned by the function not matching its declared type could also trigger the error.
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Annmarie
8 months ago
I agree, calling a function before it's defined can definitely cause that error.
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Verlene
8 months ago
I think it's actually option A, when a function shares its name with a variable defined earlier.
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Jody
8 months ago
I agree, calling a function before it's defined can definitely cause that error.
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Willis
9 months ago
I think it's option A, when a function shares its name with a variable defined earlier.
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Willis
9 months ago
I agree, calling a function before it's defined can definitely cause that error.
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