You are analyzing historic unit costs for 18'' Class 5 reinforced concrete pipe is a database. The unit costs include all costs-material, labor, equipment, and other, for the excavation, bedding, pipe and backfill. Refer to the following table:
What is the median unit cost?
The median cost is found by ordering the unit costs and selecting the middle value. The ordered costs are:
$26.78, $34.50, $37.30, $40.00, $46.59, $55.00, $55.00, $65.00, $75.00
Since there are nine data points, the fifth value in this list is the median:
C . $40.00 is the median unit cost.
A used concrete pumping truck can be purchased for $125,000. The operation costs are expected to be $65,000 the first year and increase 5% each year thereafter. As a result of the purchase, the company will see an increase in income of $100,000 the first year and 5% more each subsequent year. The company uses straight-line depreciation. The truck will have a useful life of five (5) years and no salvage value. Management would like to see a 10% return on any investment. The company's tax rate is 28%.
Assuming the average life span of a lithium battery is two years and is normally distributed with a standard deviation of two months, what is the probability the battery will last between 20 months and 26 months?
Given that the average life span of the lithium battery is 24 months with a standard deviation of 2 months, we need to calculate the probability that the battery will last between 20 and 26 months.
Using the Z-score formula:
Z=XZ = \frac{X - \mu}{\sigma}Z=X
For 20 months: Z=20242=2Z = \frac{20 - 24}{2} = -2Z=22024=2
For 26 months: Z=26242=1Z = \frac{26 - 24}{2} = 1Z=22624=1
Looking up these Z-scores in the standard normal distribution table:
Z = -2 corresponds to approximately 2.28%
Z = 1 corresponds to approximately 84.13%
The probability that the battery will last between 20 and 26 months is approximately 84%.
A used concrete pumping truck can be purchased for $125,000. The operation costs are expected to be $65,000 the first year and increase 5% each year thereafter. As a result of the purchase, the company will see an increase in income of $100,000 the first year and 5% more each subsequent year. The company uses straight-line depreciation. The truck will have a useful life of five (5) years and no salvage value. Management would like to see a 10% return on any investment. The company's tax rate is 28%.
Student will receive scholarship when the GPA is within top 2%. The mean GPA is 2.8 and standard deviation is 0.5.
How high must the GPA be to qualify for the scholarship?
To find the GPA that qualifies for the top 2%, we use the inverse of the standard normal distribution (Z-table). The Z-score corresponding to the top 2% is approximately 2.05. Given the mean GPA is 2.8 with a standard deviation of 0.5, we calculate the threshold GPA as follows:
GPA=+Z=2.8+2.050.5=2.8+1.025=3.62\text{GPA} = \mu + Z \times \sigma = 2.8 + 2.05 \times 0.5 = 2.8 + 1.025 = 3.62GPA=+Z=2.8+2.050.5=2.8+1.025=3.62
Thus, a GPA of 3.62 is needed to qualify for the scholarship.
SCENARIO: A can manufacturing company requested you to provide data for their decision making The unit prices of the can varies but an average selling price of $0.55 cents and average cost of S45 cents is estimated.
The monthly fixed costs are:
Rant-$1,500
Wages - $4.000
Miscellaneous fixed expenses - $500
If there is an additional variable cost of $0.02 per unit, the monthly break even units are:
To calculate the break-even point, we need to determine how many units must be sold to cover all fixed and variable costs. The formula to calculate the break-even point in units is:
Break-evenunits=TotalFixedCostsSellingPriceperUnitVariableCostperUnit\text{Break-even units} = \frac{\text{Total Fixed Costs}}{\text{Selling Price per Unit} - \text{Variable Cost per Unit}}Break-evenunits=SellingPriceperUnitVariableCostperUnitTotalFixedCosts
Given:
Selling Price per Unit = $0.55
Variable Cost per Unit = $0.45 + $0.02 = $0.47
Contribution Margin per Unit = $0.55 - $0.47 = $0.08
Total Fixed Costs:
TotalFixedCosts=1500+4000+500=6000\text{Total Fixed Costs} = 1500 + 4000 + 500 = 6000TotalFixedCosts=1500+4000+500=6000
Break-even units:
Break-evenunits=60000.08=75,000units\text{Break-even units} = \frac{6000}{0.08} = 75,000 \text{ units}Break-evenunits=0.086000=75,000units
Therefore, the correct answer is C. 75,000 units.
Develop a CPM method considering the below tasks and logical relationships. Use this information to answer the related questions.
What is the late finish date of activity 50?
To determine the late finish date of Activity 50 using the CPM method, you would consider the latest finish times of its successors. The path through the project network would lead to the calculation that the latest possible time that Activity 50 can finish without delaying the project is Day 37. Therefore, the correct answer is D. Day 37.
Top of Form
Bottom of Form
Charlesetta
9 days agoHolley
1 months agoScot
1 months agoJesusita
2 months agoOmega
2 months agoAntonio
3 months agoErick
3 months agoLon
3 months agoBrandee
4 months agoRhea
4 months agoHermila
4 months agoBarb
5 months agoAdell
5 months agoValda
5 months agoNichelle
5 months agoKeneth
6 months agoEarnestine
6 months agoJudy
6 months ago